Editing User:Alex the weeb/Kirby spit star duration (SSBU)

The number of frames opponents are stuck in the star for (without mashing) at 10% intervals.

{| class="wikitable"
!  !! Kirby % !! 0 !! 10 !! 20 !! 30 !! 40 !! 50 !! 60 !! 70 !! 80 !! 90 !! 100
|-
| '''Opponent %''' || || || || || || || || || || || ||
|-
| '''0''' || || 25 || 25 || 25 || 25 || 25 || 25 || 25 || 25 || 25 || 25 || 25
|-
| '''10''' || || 30 || 30 || 30 || 30 || 30 || 30 || 30 || 30 || 30 || 30 || 30
|-
| '''20''' || || 35 || 35 || 35 || 35 || 35 || 35 || 35 || 35 || 35 || 35 || 35
|-
| '''30''' || || 40 || 40 || 40 || 40 || 40 || 40 || 40 || 40 || 40 || 40 || 38
|-
| '''40''' || || 45 || 45 || 45 || 45 || 45 || 45 || 45 || 45 || 43 || 42 || 40
|-
| '''50''' || || 50 || 50 || 50 || 50 || 50 || 50 || 48 || 46 || 45 || 43 || 42
|-
| '''60''' || || 55 || 55 || 55 || 54 || 53 || 51 || 50 || 48 || 46 || 45 || 43
|-
| '''70''' || || 60 || 59 || 58 || 56 || 54 || 53 || 51 || 50 || 48 || 46 || 45
|-
| '''80''' || || 60 || 60 || 59 || 58 || 56 || 54 || 53 || 51 || 50 || 48 || 46
|-
| '''90''' || || 60 || 60 || 60 || 59 || 58 || 56 || 54 || 53 || 51 || 50 || 48
|-
| '''100''' || || 60 || 60 || 60 || 60 || 59 || 58 || 56 || 54 || 53 || 51 || 50
|}

==Technical details==
Base star duration begins at 25 frames when the opponent is at 0%, and increases by 0.5 per % of damage the opponent has, not including the added damage from the throw. Base duration will not exceed 60 frames. However, a caveat to this is that a fighter will be released automatically if the star's speed drops below a value of 0.4 units/frame, regardless of how many star frames are left. The parameters for star speed (in units/frame) are:

*Base speed 2.8
*Additional speed = 0.008p<sub>o</sub> - 0.008p<sub>k</sub> where p<sub>o</sub> is the opponent's percent and p<sub>k</sub> is Kirby's percent
*Speed decay per frame = 0.05

This gives an initial speed formula of 2.8 + 0.008(p<sub>o</sub> - p<sub>k</sub>). Overall, the base duration formula is 25 + 0.5d, and for the frames until a forced release, the equation is found to be (2.4 + 0.008(p<sub>o</sub> - p<sub>k</sub>))/0.05 + 2, which simplifies to 50 + 0.16(p<sub>o</sub> - p<sub>k</sub>).
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	This gives an initial speed formula of 2.8 + 0.008(p<sub>o</sub> - p<sub>k</sub>). Overall, the base duration formula is 25 + 0.5d, and for the frames until a forced release, the equation is found to be (2.4 + 0.008(p<sub>o</sub> - p<sub>k</sub>))/0.05 + 2, which simplifies to 50 + 0.16(p<sub>o</sub> - p<sub>k</sub>).		This gives an initial speed formula of 2.8 + 0.008(p<sub>o</sub> - p<sub>k</sub>). Overall, the base duration formula is 25 + 0.5d, and for the frames until a forced release, the equation is found to be (2.4 + 0.008(p<sub>o</sub> - p<sub>k</sub>))/0.05 + 2, which simplifies to 50 + 0.16(p<sub>o</sub> - p<sub>k</sub>).

	~~Thanks to [[User:CanvasK\|CanvasK]] for helping with the technical data.~~
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